The deformation principle is a fundamental theorem in complex analysis that establishes a crucial property of holomorphic functions. It states that the integral of a holomorphic function around a closed contour in the complex plane remains unchanged if the contour is continuously deformed without passing through any singularities of the function. This principle provides a powerful tool for solving complex integrals and understanding the behavior of holomorphic functions.
Let (f(z)) be a holomorphic function on an open set containing a closed, rectifiable contour (\gamma). Suppose that there are no singularities of (f(z)) within or on the contour (\gamma). Then, the integral of (f(z)) around (\gamma) is independent of the choice of (\gamma), as long as it is continuously deformed within the open set. In other words:
$$\oint_\gamma f(z) dz = \oint_{\gamma'} f(z) dz$$
where (\gamma') is any other closed, rectifiable contour that can be continuously deformed into (\gamma) without passing through any singularities of (f(z)).
The proof of the deformation principle relies on the Cauchy integral formula. Let (f(z)) be holomorphic on an open set containing a closed contour (\gamma). Then, for any point (z_0) within (\gamma), we have:
$$f(z_0) = \frac{1}{2\pi i} \oint_\gamma \frac{f(z)}{z-z_0} dz$$
Using this formula, we can show that the integral of (f(z)) around (\gamma) is independent of the choice of (\gamma).
Let (\gamma_1) and (\gamma_2) be two closed, rectifiable contours that can be continuously deformed into each other without passing through any singularities of (f(z)). We can divide the region between (\gamma_1) and (\gamma_2) into a sequence of smaller regions by drawing a series of parallel lines.
By the Cauchy integral formula, the integral of (f(z)) around each of these smaller regions is zero. Therefore, the integral of (f(z)) around (\gamma_1) must be equal to the integral of (f(z)) around (\gamma_2).
The deformation principle is widely used in complex analysis to:
Example 1: Evaluate the integral of (f(z) = 1/(z-1)) around the unit circle centered at the origin.
Solution: The function (f(z) = 1/(z-1)) has a singularity at (z=1), which is inside the unit circle. By the deformation principle, we can deform the unit circle to any other contour that does not pass through (z=1), such as the circle of radius 2 centered at the origin. The integral of (f(z)) around this contour is then given by the Cauchy integral formula:
$$\oint_{|z|=2} \frac{1}{z-1} dz = 2\pi i$$
Example 2: Prove that the function (f(z) = e^z) is entire (i.e., it has no singularities).
Solution: By the deformation principle, the integral of (f(z)) around any closed contour in the complex plane is zero. This is because (f(z)) is holomorphic everywhere, so it has no singularities. Therefore, (f(z)) is entire.
The deformation principle can be extended to more general situations, such as:
The deformation principle is a powerful tool in complex analysis that provides a deep understanding of the behavior of holomorphic functions. It is used to solve complex integrals, prove important theorems, and extend holomorphic functions to larger domains. The principle is fundamental to many areas of mathematics, including algebraic geometry, topology, and number theory.
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